Q. 204.2( 6 Votes )

In Fig. 2,

Answer :

The figure can be redrawn as follows:


It is given in the question that,


AB = 12 cm


BC = 8 cm


AC = 10 cm


As we know that, tangents drawn from an external point in a triangle are equal


AF = AD, CF = CE, BD = BE


Let us assume AD = AF = x cm


DB = AB – AD


= (12 – x) cm


Also, BE = (12 – x) cm


Similarly,


CF = CE = AC – AF


= (10 – x) cm


As, BC = 8 cm


BE + CE = 8


12 – x + 10 – x = 8


22 – 8 = 2x


2x = 14


x = 7 cm


Hence, AD = x = 7 cm


BE = 12 – x


= 12 – 7


= 5 cm


And, CF = 10 – x


= 10 – 7


= 3 cm

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