Q. 205.0( 2 Votes )

In ΔABC, B = 90° and BD AC. Prove that ABD = ACB.


Answer :


Let ABD = x and ACB = y


According to question,


B = 90O


In triangle BDC, we have,


BDC = 90O


DBC = (90 – x)O


BDC + DBC + DCB = 180O


90O + (90 – x)O + y = 180O


180O – x + y = 180O


x = y


So,


ABD = ACB


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