Q. 205.0( 2 Votes )

# In ΔABC, ∠B = 90° and BD ⊥ AC. Prove that ∠ABD = ∠ACB.

Answer :

Let ABD = x and ACB = y

According to question,

B = 90O

In triangle BDC, we have,

BDC = 90O

DBC = (90 – x)O

BDC + DBC + DCB = 180O

90O + (90 – x)O + y = 180O

180O – x + y = 180O

x = y

So,

ABD = ACB

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