Q. 203.7( 4 Votes )
If an angle of a A. 108°
B. 54°
C. 72°
D. 81°
Answer :
Given,
In parallelogram ABCD
∠A+∠B = 180° [adjacent angles of parallelogram are supplementary]
∠ A = 
So, 
= 
= 
∠A = 
Thus smallest angle of parallelogram is 72°
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