Answer :


Let AB be the building and CE be the tower


Given the height of the building, AB = 7m


To find: Height of tower, i.e. CE


From the top of building, angle of elevation of the top of tower = 60°


Hence,EAD = 60°


The angle of depression of the foot of the tower = 45°


Hence,CAD = 45°


Since AB and CD are parallel


CD = AB = 7m


Also,


AD and BC are parallel


So, AD = BC


Since tower and building are vertical to the ground


ABC = 90° andEDA = 90°


Now, AD and BC are parallel


Taking AC as transversal


ACB =DAC = 45° [Alternate angles]


Now, In Δ ABC, we have





BC = 7m …(i)


Since BC = AD


So, AD = 7m


Now, In ΔADE, we have



[from(i)]



ED = 7√3 m


Hence, the height of the tower, CE = ED + DC


= 7√3 + 7


= 7(√3 +1)m


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