Q. 205.0( 2 Votes )

Find that value o

Answer :

(p + 1)x2-6(p + 1)x + 3(p + 9)=0

This is a quadratic equation of form ax2 + bx + c=0

Where a=p + 1, b=-6(p + 1) ,c=3(p + 9)

For equal roots, D=0


Substituting the values of a,b and c

(-6(p + 1))2-4(p + 1)3(p + 9)=0

36(p2 + 1 + 2p)-12(p2 + 10p + 9)=0



p2-3p + p-3=0

p(p-3) + 1(p-3)=0

(p + 1)(p-3)=0

There are two possible values of p, p=-1 and p=3

We neglect p=-1 as on putting p=-1; the equation does not remain quadratic.

p=3 is our required value of p.


As we know roots are equal,

Therefore, each root=

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