Q. 203.9( 8 Votes )

# Evaluate:<s

Answer :

Let,

Now

Let

Put x = -x in f(x)

As, (-x)2 = (x)2 and |-x| = |x|, we get,

f(-x) = - f(x)

As f(-x) = - f(x)

So, f(x) is an odd function

We know that if g(x) is an odd function-

Therefore, I1 = 0

Now

Let

Put x = -x in g(x)

As, (-x)2 = (x)2 and |-x| = |x|, we get,

As, g(-x) = g(x)

So, g(x) is an even function.

We know that if h(x) is an even function-

I2 = 2(log 2 – log 1)

I2 = 2log 2

Therefore, I = 2 log 2

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