Q. 203.9( 8 Votes )

Evaluate:<s

Answer :

Let,




Now


Let


Put x = -x in f(x)



As, (-x)2 = (x)2 and |-x| = |x|, we get,




f(-x) = - f(x)


As f(-x) = - f(x)


So, f(x) is an odd function


We know that if g(x) is an odd function-



Therefore, I1 = 0


Now


Let


Put x = -x in g(x)



As, (-x)2 = (x)2 and |-x| = |x|, we get,




As, g(-x) = g(x)


So, g(x) is an even function.


We know that if h(x) is an even function-







I2 = 2(log 2 – log 1)


I2 = 2log 2


Therefore, I = 2 log 2


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