Q. 205.0( 1 Vote )

# A and B are two e

Given, P(A) = 0.25 and P(B) = 0.5

Also P(A B) = 0.14

We have to find P(A’ B’)

By De Morgan’s theorem we know that:

P(A’ B’) = P(A B)’

We know that P(A B) = P(A) + P(B) – P(A B)

P(A B) = 0.25 + 0.5 – 0.14 = 0.61

P(A’ B’) = P(A B)’ = 1 -P(A B) = 1 – 0.61 = 0.39

As our answer matches with option (a)

Option (a) is the only correct choice.

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