sin(x) has maximum value at x = π/2 and its minimum at
x = -π/2 which are 1 and -1 respectively.
As 1 < π/2;
so, the argument of the outer sin always lies within the interval
So the maximum and minimum of the given function are
sin 1 and - sin 1.
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<span lang="EN-USRS Aggarwal - Mathematics
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