Q. 25.0( 4 Votes )

Two poles of heig A. 9 m

B. 10 m

C. 11 m

D. 12 m

Answer :


Let AB and CE be the two poles of the height 13 cm and 7 cm each which are perpendicular to the ground. The distance between them is 8 cm.


Now since CE and AB are ground AE


BD to CE and BD = 8 cm


Top of pole AB is B and top of pole CE is C


Now Δ BDC is right angled at D and BC, the hypotenuse is the distance between the top of the poles and CD = 13 – 7 = 6


(BC)2 = (BD) 2 + (CD)2


(BC)2 = 64 + 36


(BC)2 = 100


(BC)= 10 cm


The distance between the top of the poles is 10 cm

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