Q. 25.0( 4 Votes )

# Two poles of heig A. 9 m

B. 10 m

C. 11 m

D. 12 m

Answer :

Let AB and CE be the two poles of the height 13 cm and 7 cm each which are perpendicular to the ground. The distance between them is 8 cm.

Now since CE and AB are ⊥ ground AE

BD ⊥ to CE and BD = 8 cm

Top of pole AB is B and top of pole CE is C

Now Δ BDC is right angled at D and BC, the hypotenuse is the distance between the top of the poles and CD = 13 – 7 = 6

(BC)^{2} = (BD) ^{2} + (CD)^{2}

⇒ (BC)^{2} = 64 + 36

⇒ (BC)^{2} = 100

⇒ (BC)= 10 cm

The distance between the top of the poles is 10 cm

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