Q. 24.2( 45 Votes )

The value of the

Answer :

We have,


cosec(75°+θ) – sec(15°-θ) - tan(55°+θ) + cot(35°-θ)


= cosec[90°-(15°-θ)] – sec(15°-θ) – tan(55°+θ) + cot[90°-(55°+θ)]


= sec(15°-θ) – sec(15°-θ) - tan(55°+θ) + tan(55°+θ) ( cosec (90°- θ) = sec θ and cot(90°-θ) = tan θ)


= 0


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