Q. 23.9( 22 Votes )

<span lang="EN-US

Answer :

(i) The two radii of frustum are, r1 = 14cm and r2= 6cm


Height of frustum, H = 6cm


Slant height of frustum,




l = 10


As we know that,


Curved surface area, AC = πl(r1 + r2)


AC = (3.14) × 10 × (14 + 6)


AC = (3.14) × 200


AC = 628 sq. cm


the curved surface area of frustum is 628 sq. cm


(ii) Total surface area, AT = Curved surface area + area of the two circular regions


AT = AC + πr12 + πr22


On substituting the above values, we get,


AT = 628 + (3.14) × (142 + 62)


AT = 628 + (3.14)× (196 + 36)


AT = 628 + 728.48


AT = 1356.48 sq. cm


the total surface area of frustum is 1356.48 cm2


(iii) As we know,



On substituting the values, we get,





V = 1984.48 cm3


Volume of the frustum is 1984.48 cm3


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USMHB - Mathematics Part-2

<span lang="EN-USMHB - Mathematics Part-2

<span lang="EN-USMHB - Mathematics Part-2

<span lang="EN-USMHB - Mathematics Part-2