Q. 23.9( 22 Votes )

# <span lang="EN-US

Answer :

(i) The two radii of frustum are, r1 = 14cm and r2= 6cm

Height of frustum, H = 6cm

Slant height of frustum,   l = 10

As we know that,

Curved surface area, AC = πl(r1 + r2)

AC = (3.14) × 10 × (14 + 6)

AC = (3.14) × 200

AC = 628 sq. cm

the curved surface area of frustum is 628 sq. cm

(ii) Total surface area, AT = Curved surface area + area of the two circular regions

AT = AC + πr12 + πr22

On substituting the above values, we get,

AT = 628 + (3.14) × (142 + 62)

AT = 628 + (3.14)× (196 + 36)

AT = 628 + 728.48

AT = 1356.48 sq. cm

the total surface area of frustum is 1356.48 cm2

(iii) As we know, On substituting the values, we get,   V = 1984.48 cm3

Volume of the frustum is 1984.48 cm3

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