Answer :

For figure 1,

Side of square = 3 cm

If, Side of square = a cm

Diagonal of square = =

As seen in figure,

Diameter of circle = Diagonal of square

∴ Diameter of circle = √2 × 3 cm

∴ Radius of circle =

If r = radius of circle

Area of circle = π × r^{2} cm^{2}

= ()^{2}

= cm^{2}

≈3.144.5

≈14.13 cm^{2}

For figure 2,

From Pythagoras theorem,

(Hypotenuse)^{2} = (one side)^{2} + (other side)^{2}

Diagonal of rectangle = (4^{2} + 2^{2})^{1/2}

= (16 + 4)^{1/2}

= √20 cm

As seen from figure,

Diagonal of rectangle = Diameter of circle = √20 cm

∴ Radius of circle =

If r = radius of circle

Area of circle = π × r^{2} cm^{2}

= ()^{2}

= cm^{2}

≈3.1415200

≈628.3 cm^{2}

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