# The length of a r

Let the length be ‘x’ and breadth be ‘y’.

x = y + 1 … (1)

Area of rectangle = Length × breadth

15 = 4(y2 + y)

15 = 4y2 + 4y

4y2 + 4y – 15 = 0

4y2 – 6y + 10y – 15 = 0

2y (2y – 3) + 5(2y – 3) = 0

(2y – 3) (2y + 5) = 0

2y – 3 = 0 or 2y + 5 = 0

Hence, side of a rectangle cannot be negative. Therefore,

Put in equation (1)

The length is metre and breadth are metre.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Equations of Motion41 mins
Pair of Angles29 mins
Angle Sum Property29 mins
Parallel Lines and Transversal Lines22 mins
Conservation of Energy41 mins
Division of Polynomials46 mins
Complete Basics of Class 9 Chemistry - I35 mins
Graphical Representation of Motion - II39 mins
Graphical Representation of Motion - I44 mins
Work and Types of Work done40 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

If the length of Kerala Board Mathematics Part-1

Four times a numbKerala Board Mathematics Part-1

Raju bought sevenKerala Board Mathematics Part-1

A 10-metre-long rKerala Board Mathematics Part-1

The length of a rKerala Board Mathematics Part-1

The sum of the diKerala Board Mathematics Part-1

The hypotenKerala Board Mathematics Part-1

Four years ago, RKerala Board Mathematics Part-1