Mark against the A.
B. 0, 1, 0
C. 0, -1, 0
D. None of these
Given: Equation of plane is 5y + 4 = 0
Formula Used: Equation of a plane is lx + my + nz = p where (l, m, n) are the direction cosines of the normal to the plane and (x, y, z) is a point on the plane and p is the distance of plane from origin.
Given equation is 5y = -4
Dividing by -5,
which is of the form lx + my + nz = p where l = 0, m = -1, n = 0
Therefore, direction cosines of the normal to the plane is (0, -1, 0)
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