Answer :

Given: diameter of the cylindrical roller = 80cm

Length of the roller (height of the cylinder) = 1.2m = 120cm

To find: area of leveled surface, when it rolls once = ?

Procedure:

When the cylindrical roller will roll once on the road, the area of the leveled surface will be equal to the lateral surface area of the roller because on rolling once it will cover the distance equal to its lateral surface area.

So, now, lateral surface area of the roller = perimeter of base of cylinder × height of cylinder

⇒lateral surface area of the roller = (2∏r)× h

= (∏d)× h

= 3.14× 80× 120

lateral surface area of the roller = 30,144cm^{2}

∴ when the cylindrical roller rolls once, the area of the leveled surface is 30,144cm^{2}

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