Q. 23.8( 19 Votes )

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Answer :

f(x) = 7x – 3


Now f(x) is strictly increasing iff f’(x) > 0


Let us calculate f’(x)


Differentiate f(x) with respect to x


f’(x) = 7


Hence f’(x) is constant


7 > 0 for all values of x hence f’(x) > 0


As f’(x) > 0, f(x) is strictly increasing


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