Q. 24.0( 77 Votes )
∆ PQR ~ ∆ LTR. In ∆ PQR, PQ = 4.2 cm, QR = 5.4 cm, PR = 4.8 cm. Construct ∆ PQR and ∆ LTR, such that 
Answer :
Steps of construction:
i. Draw a triangle PQR, with PQ = 4.2 cm, QR = 5.4 cm and PR = 4.8 cm, choosing QR = 5.4 cm as base.
ii. Below QR, draw an acute angle ∠QRX.
iii. Mark four points R1, R2, R3 and R4 on RX, such that RR1 = R1R2 = R2R3 = R3R4. [As ratio is 4:3, we choose 4 points]
iv. Join QR4 and Draw TR3 || QR4
v. Draw LT || PQ.
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