Q. 23.9( 24 Votes )

Look at the measu

Answer :

In the given fig. ∆ PRS is right angle triangle at S


Therefore, using Pythagoras theorem,


PS2 + SR2 = PR2




= 39m


Now,


Area of ∆PRS = × base × height


= ×PS×SR


= ×36×15


= 270 sq m


Now the area of triangle PQR, using heron’s formula


Here, sides are 56 cm, 25 cm, and 39 cm


Therefore,


S = 60


S - a = 60 - 56 = 4


S - b = 60 - 25 = 35


S - c = 60 - 39 = 21




= 420 sq m


Hence, the area of the quadrilateral PQRS = area of ∆PQR + ∆PSR


= 420 + 270


= 690 sq m


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