Answer :

In the given fig. ∆ PRS is right angle triangle at S

Therefore, using Pythagoras theorem,

PS^{2} + SR^{2} = PR^{2}

= 39m

Now,

**Area of ∆PRS =** **× base × height**

= ×PS×SR

= ×36×15

= 270 sq m

Now the area of triangle PQR, using heron’s formula

Here, sides are 56 cm, 25 cm, and 39 cm

Therefore,

S = 60

S - a = 60 - 56 = 4

S - b = 60 - 25 = 35

S - c = 60 - 39 = 21

= 420 sq m

Hence, the area of the quadrilateral PQRS = area of ∆PQR + ∆PSR

= 420 + 270

**= 690 sq m**

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

Some measures areMHB - Mathematics (New)

Look at the measuMHB - Mathematics (New)

Sides of a triangMHB - Mathematics (New)