# <span lang="EN-US

We know sum of all interior angles of a triangle is 180⁰.

In ∆ABC,

a + b + c = 180⁰

40⁰ + 60⁰ + c = 180⁰

100⁰ + c = 180⁰

c = 180⁰-100⁰

c = 80⁰

To find all angles in ∆PQR:

Given, AB = QR

BC = RP

CA = PQ

To find pairs of matching angles, the angles between any two of the corresponding sides in the two figures are matching angles.

Thus,

CAB = PQR = 40⁰

ABC = QRP = 60⁰

BCA = RPQ = 80⁰

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