Answer :

We know sum of all interior angles of a triangle is 180⁰.

In ∆ABC,


a + b + c = 180⁰


40⁰ + 60⁰ + c = 180⁰


100⁰ + c = 180⁰


c = 180⁰-100⁰


c = 80⁰


To find all angles in ∆PQR:


Given, AB = QR


BC = RP


CA = PQ


To find pairs of matching angles, the angles between any two of the corresponding sides in the two figures are matching angles.


Thus,


CAB = PQR = 40⁰


ABC = QRP = 60⁰


BCA = RPQ = 80⁰


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