# In the road of ou

Given: Length of ladder, l = 15 m

Now, the situation can be shown in a diagram as: As the wall is always perpendicular to the floor or road, so ΔAFD and ΔBFC are right angled triangle.

To find broad first we need to find the lengths AF and FB.

In right ΔAFD,

h = 15 m

p = 12 m

b = AF

By applying Pythagoras theorem, we have,

h2 = p2 + b2

152 = 122 + AF2

225 = 144 + AF2

AF2= 225 – 144

AF2 = 121

AF = √121

AF = 11 m …………………… (1)

In right ΔBFC,

h = 15 m

p = 9 m

b = FB

By applying Pythagoras theorem, we have,

h2 = p2 + b2

152 = 92 + FB2

225 = 81 + FB2

FB2 = 225 – 81

FB2 = 144

FB = √144

FB = 12 m …………………… (2)

Now,

Substituting from eqn. (1) and (2), we have,

broad = 11 + 12 m

Therefore, the breath of road is 13 m.

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