Answer :

Given: Length of ladder, l = 15 m


Now, the situation can be shown in a diagram as:



As the wall is always perpendicular to the floor or road, so ΔAFD and ΔBFC are right angled triangle.


Here broad represents breadth of road.


To find broad first we need to find the lengths AF and FB.


In right ΔAFD,


h = 15 m


p = 12 m


b = AF


By applying Pythagoras theorem, we have,


h2 = p2 + b2


152 = 122 + AF2


225 = 144 + AF2


AF2= 225 – 144


AF2 = 121


AF = √121


AF = 11 m …………………… (1)


In right ΔBFC,


h = 15 m


p = 9 m


b = FB


By applying Pythagoras theorem, we have,


h2 = p2 + b2


152 = 92 + FB2


225 = 81 + FB2


FB2 = 225 – 81


FB2 = 144


FB = √144


FB = 12 m …………………… (2)


Now,


broad = AF + FB


Substituting from eqn. (1) and (2), we have,


broad = 11 + 12 m


broad = 13 m


Therefore, the breath of road is 13 m.


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