Answer :
(1) Given PQRS is a cyclic quadrilateral.
∵Opposite angles of a cyclic quadrilateral are supplementary
⇒∠ PSR + ∠ PQR = 180°
⇒∠ PQR = 180° - 110°
⇒∠ PQR = 70°
(2)2 × ∠ PQR = m(arc PR){The measure of an inscribed angle is half the measure of the arc intercepted by it.}
m(arc PR) = 140°
⇒m(arc PQR) = 360° -140° = 220° {Using Measure of a major arc = 360°- measure of its corresponding minor arc}
(3)side PQ ≅ side RQ
∴m(arc PQ) = m(arc RQ){Corresponding arcs of congruent chords of a circle (or congruent circles) are congruent}
⇒m(arc PQR) = m(arc PQ) + m(arc RQ)
⇒m(arc PQR) = 2 × m(arc PQ)
⇒m(arc PQ) = 110°
(4)In ∆ PQR,
∠ PQR + ∠ QRP + ∠ RPQ = 180°{Angle sum property}
⇒∠ PRQ + ∠ RPQ = 180° - ∠ PQR
⇒ 2∠ PRQ = 180° - 70° {∵side PQ ≅ side RQ}
⇒∠ PRQ = 55°
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