Answer :

**Given:** a = 3.5, d = 0 and n = 101

**To find:** The value of a_{n.}

**Formula Used:** nth term of an AP is:

a_{n =} a + (n - 1) d

**Explanation:**

As we know, nth term of an AP is

a_{n =} a + (n - 1) d

where a = first term

a_{n} is nth term

d is the common difference

a_{n} = 3.5 + (101 - 1 )0

= 3.5

(Here we have given d = 0, therefore it’s a constant A.P. therefore it’s all terms will be equal and constant)

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

Arithmetic Progression and 'nth' Term of AP55 mins

Imp Qs Practice For Boards (AP)59 mins

Sum of n Terms of AP56 mins

Introduction of Geometric Progression60 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation