Q. 25.0( 4 Votes )

In a ΔABC, if A – B = 40° and B – C = 10°, find the measure of A, B and C.

Answer :

A = B + 40


C = B – 10


A + B + C = 180


B + 40 + B + B – 10 = 180


3B + 30 = 180


3B = 180 – 30 = 150


B = 50O


So, A = B + 40 = 90O


C = B – 10 = 40O


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