Q. 25.0( 4 Votes )
In a ΔABC, if ∠A – ∠B = 40° and ∠B – ∠C = 10°, find the measure of ∠A, ∠B and ∠C.
Answer :
A = B + 40
C = B – 10
A + B + C = 180
B + 40 + B + B – 10 = 180
3B + 30 = 180
3B = 180 – 30 = 150
B = 50O
So, A = B + 40 = 90O
C = B – 10 = 40O
Rate this question :






















The sides BC, BA and CA of ΔABC have been produced to D, E and F respectively, as shown in the given figure. Then, ∠B = ?
In the given figure, AB || CD. If ∠EAB = 50° and ∠ECD = 60°, then ∠AEB = ?
In the given figure, x = ?
The angles of a triangle are in the ratio 3:2:7. Find the measure of each of its angles.
RS Aggarwal & V Aggarwal - MathematicsIn ΔABC, ∠B = 90° and BD ⊥ AC. Prove that ∠ABD = ∠ACB.
In ΔABC, BD ⊥ AC, ∠CAE = 30° and ∠CBD = 40°. Then ∠AEB = ?
In the given figure, ∠BAC = 30°, ∠ABC = 50° and ∠CDE = 40°. Then ∠AED = ?
In a ΔABC its is given that ∠A : ∠B : ∠C = 3 : 2 : 1 and CD ⊥ AC. Then ∠ECD = ?
Side BC of ΔABC has been produced to D on left hand side and to E on right hand side such that ∠ABD = 125° and ∠ACE = 130°. Then ∠A = ?
An exterior angle of a triangle is 110° and one of its interior opposite angles is 45°, then the other interior opposite angle is
RS Aggarwal & V Aggarwal - Mathematics