Q. 2
If α, β, γ are the zeros of the polynomial x3 – 6x2 – x + 30 then the value of (αβ + βγ + γ α) is
A. ‒1
B. 1
C. ‒5
D. 30
Answer :
We have,
p (x) = x3 – 6x2 – x + 3
Now we will compare the given polynomial with: x3 – (
) x2 + (
) x – 
By comparing we get:
(
) = - 1
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