Q. 2

# If α, β, γ are the zeros of the polynomial x^{3} – 6x^{2} – x + 30 then the value of (αβ + βγ + γ α) is

A. ‒1

B. 1

C. ‒5

D. 30

Answer :

We have,

p (x) = x^{3} – 6x^{2} – x + 3

Now we will compare the given polynomial with: x^{3} – () x^{2} + () x –

By comparing we get:

() = - 1

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