# If α, β are the zeros of the polynomial p(x) = 4x2 + 3x + 7, then =A. B. C. D.

Given,

p(x) = 4x2 + 3x + 7

α + β = – b/a

= – 3x/4x2 = – 3/4x ………. (i)

αβ = c/a

= 7/4x2 …………. (ii)

Dividing (i) from (ii),

We get,

So,

1/α + 1/β = – 3/7

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