Answer :

The probability distribution of X is:



We Know that



Therefore,


2k4+3k2-5k3+2k-3k2+3k-1=1


2k4-5k3+5k-2=0


2(k4-1)-5k2-1)=0


2(k2-1)(k2+1)-5k(k-1)(k+1)=0


2(k-1)(k+1)(k2+1)-5k(k-1)(k+1)=0


(k-1)(k+1)(2(k2+1)-5k=0


(k-1)(k+1)(2k2-5k+2)=0


(k-1)(k+1)(2k2-k-4k+2)=0


(k-1)(k+1)(k(2k-1)-2(2k-1))=0


(k-1)(K+1)(2k-1)(k-2)


k-1=0





K+1=0





2k-1=0





k-2=0





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