Answer :

Now we have been given a quadrilateral ABCD:


Case 1 : let us now draw a diagonal BD in quadrilateral ABCD



● Draw a circle considering, BD as a diagonal.



● As A and C are larger then 90° . Thus, point A and C lies inside the circle.


(As seen above, point on a circle, such an angle is a right angle.


Point outside the circle , such an angle is larger than 90°


Point inside the circle, such an angle is smaller than 90° )


Case 2: let us now draw a diagonal AC in quadrilateral ABCD



Also, By angle sum property of quadrilateral


A + B + C + D = 360°


105° + B + 110° + 55° = 360°


B + 270° = 360°


B = 360° – 270° = 90°


● Draw a circle considering, AC as a diagonal.



● As B is 90° . Thus, point B lies on the circle.


As D is smaller then 90°. Thus, point D lies outside the circle.


(As seen above, point on a circle, such an angle is a right angle.


Point outside the circle , such an angle is larger than 90°


Point inside the circle, such an angle is smaller than 90° )


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