Answer :

To draw altitudes of a triangle:

i. Draw an acute-angled ∆PQR.



ii. Draw a perpendicular from vertex P on the side QR using a set - square. Name the point where it meets side QR as M. Seg PM is an altitude on side QR.



iii. Considering side PR as a base, draw an altitude QX on side XZ. Seg QX is an altitude on side PR.



iv. Consider side PQ as a base, draw an altitude RN on seg PQ. Seg RN is an altitude on side PQ.



Hence,



Seg PM, seg QO, seg RN are the altitudes of ∆PQR. The point of concurrence i.e., the orthocentre is denoted by the point O.


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