Answer :

**Steps of construction**

1. Draw a line BC=12 cm.

2. Draw an arc of 5 cm from B and draw a line AB=5 cm.

3. Join AC.

4. Draw an acute CBY downwards.

** _{1.}** On ray BY, mark three-point B

_{1}, B

_{2,}and B

_{3,}

BB_{1}=B_{1}B_{2} =B_{2}B_{3}

6. Join B_{3} C

7. Draw B_{2}N||B_{3}C intersect BC at N.

8. Draw NM||CA intersect BA at M.

∆MBN is the required triangle.

Hence, ∆MBN is also a right-angled triangle at B.

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