Q. 24.1( 40 Votes )

Diameter of a circle is 26 cm and length of a chord of the circle is 24 cm. Find the distance of the chord from the center.

Answer :

Given that diameter = 26cm

Radius = Diameter / 2 = 26 /2 = 13cm

So, OA = 13cm

And AB = 24 cm

We know that a perpendicular drawn from the center of a circle on its chord bisects

the chord.

AP = PB = 12 cm

In the right angled ΔOAP using Pythagoras theorem,

OA2 = OP2 + AP2

132 = OP2 + 122

169 = OP2 + 144

OP2 = 25

OP = 5cm

So, the distance of chord from the center is 5cm.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Concept of Cyclic Quadrilateral61 mins
Master Theorems in Circles42 mins
Genius Quiz | Rolling Around Circles49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses