Q. 24.1( 40 Votes )

Diameter of a circle is 26 cm and length of a chord of the circle is 24 cm. Find the distance of the chord from the center.

Answer :


Given that diameter = 26cm


Radius = Diameter / 2 = 26 /2 = 13cm


So, OA = 13cm


And AB = 24 cm


We know that a perpendicular drawn from the center of a circle on its chord bisects


the chord.


AP = PB = 12 cm


In the right angled ΔOAP using Pythagoras theorem,


OA2 = OP2 + AP2


132 = OP2 + 122


169 = OP2 + 144


OP2 = 25


OP = 5cm


So, the distance of chord from the center is 5cm.


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