Construct ΔXYZ in which ∠Y =58°, ∠X = 46° and perimeter of triangle is 10.5 cm.
Given: ∠Y =58°, ∠X = 46° and perimeter of Δ PQR
Steps of construction:
i: Draw a line segment QR of 10.5cm.
ii: From point Q draw a ray QD at 58° and from R draw a ray RE at 46°
iii: Draw an angle bisector of Q and R, two angle bisectors intersect each other at point X.
iv: Draw a line bisector of QX and XR respectively these two-line bisectors intersect at point Y and Z
v: Join XY AND XZ.
vi: Δ XYZ is required triangle.
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