Q. 2

Construct ΔXYZ in which Y =58°, X = 46° and perimeter of triangle is 10.5 cm.

Answer :

Given: Y =58°, X = 46° and perimeter of Δ PQR

Steps of construction:


i: Draw a line segment QR of 10.5cm.



ii: From point Q draw a ray QD at 58° and from R draw a ray RE at 46°



iii: Draw an angle bisector of Q and R, two angle bisectors intersect each other at point X.



iv: Draw a line bisector of QX and XR respectively these two-line bisectors intersect at point Y and Z



v: Join XY AND XZ.



vi: Δ XYZ is required triangle.


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