Q. 24.0( 22 Votes )

Construct Δ PQR, in which QR = 6.5cm, PQR = 60° and PQ-PR = 2.5cm

Answer :

Given: Base QR = 6.5cm,

PQ-PR = 2.5cm and


Q = 60° of Δ PQR.


Required: To construct a triangle PQR.


Steps of construction:


i: Draw a segment QR of length 6.5cm.



ii: Draw ray QL such that Q = 60°



iii: Mark an arc on opposite ray QL i.e. QS cutting at D such that QD = 2.5cm.



iv: Draw segment RD.



v: Construct the perpendicular bisector of segment RD.



vi: Name the point of intersection of ray QL and the perpendicular bisector of RD as P.



vii: Draw segment PR.



ΔPQR is the required triangle.


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