Q. 24.0( 22 Votes )
Construct Δ PQR, in which QR = 6.5cm, ∠PQR = 60° and PQ-PR = 2.5cm
Given: Base QR = 6.5cm,
PQ-PR = 2.5cm and
∠Q = 60° of Δ PQR.
Required: To construct a triangle PQR.
Steps of construction:
i: Draw a segment QR of length 6.5cm.
ii: Draw ray QL such that ∠Q = 60°
iii: Mark an arc on opposite ray QL i.e. QS cutting at D such that QD = 2.5cm.
iv: Draw segment RD.
v: Construct the perpendicular bisector of segment RD.
vi: Name the point of intersection of ray QL and the perpendicular bisector of RD as P.
vii: Draw segment PR.
ΔPQR is the required triangle.
Rate this question :
Construct Δ ABC, in which BC= 6.2cm, ∠C = 50°, AB+AC= 9.8cmMHB - Math Part-II
Construct Δ PQR, in which PQ-PR= 2.4cm, QR= 6.4cm and ∠PQR = 55°.MHB - Math Part-II
The perimeter of a triangle is 14.4 cm and the ratio of lengths of its side is 2: 3: 4. Construct the triangle.MHB - Math Part-II
Construct Δ XYZ, in which YZ= 7.4cm, ∠XYZ = 45° and XY-XZ= 2.7cmMHB - Math Part-II
Construct ΔXYZ, in which YZ= 6cm, XY+XZ= 9cm and ∠Y = 50°MHB - Math Part-II
Construct Δ PQR, in which ∠Q =70°, ∠R = 80° and PQ+QR+PR=9.5cmMHB - Math Part-II
Construct Δ ABC, in which ∠B =70°, ∠C = 60°, AB+BC+AC=11.2cm.MHB - Math Part-II
Construct ΔLMN, in which ∠M =60°, ∠N =80° and LM+MN+NL=11cm.MHB - Math Part-II