Given: ∠B =70°, ∠C = 60° and perimeter of Δ ABC
Steps of construction:
i: Draw a line segment PQ of 11.2cm.
ii: From point P draw a ray PD at 70° and from Q draw a ray QE at 60°
iii: Draw an angle bisector of P and Q, two angle bisectors intersect each other at point A.
iv: Draw a line bisector of AP and AQ respectively these two-line bisectors intersect at point B and C
v: Join AB AND AC
vi: Δ ABC is required triangle.
Rate this question :