Q. 23.6( 13 Votes )

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Answer :

Given: B =70°, C = 60° and perimeter of Δ ABC

Steps of construction:

i: Draw a line segment PQ of 11.2cm. ii: From point P draw a ray PD at 70° and from Q draw a ray QE at 60° iii: Draw an angle bisector of P and Q, two angle bisectors intersect each other at point A. iv: Draw a line bisector of AP and AQ respectively these two-line bisectors intersect at point B and C v: Join AB AND AC vi: Δ ABC is required triangle.

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