# <span lang="EN-US

Given: B =70°, C = 60° and perimeter of Δ ABC

Steps of construction:

i: Draw a line segment PQ of 11.2cm.

ii: From point P draw a ray PD at 70° and from Q draw a ray QE at 60°

iii: Draw an angle bisector of P and Q, two angle bisectors intersect each other at point A.

iv: Draw a line bisector of AP and AQ respectively these two-line bisectors intersect at point B and C

v: Join AB AND AC

vi: Δ ABC is required triangle.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Revision on Angle sum Property of Triangles44 mins
Master Mole Concept in 45 Minutes48 mins
Newton's Second Law46 mins
Master the Art of Writing Chemical Formulae42 mins
Law of Gravitation40 mins
Combinations of Solids43 mins
Quick Recap of Cell62 mins
Circles- All kinds of Questions36 mins
Laws of Chemical Combination - Part 140 mins
Final Phase & Legacy of the Revolution43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

<span lang="EN-USMHB - Math Part-II

<span lang="EN-USMHB - Math Part-II

<span lang="EN-USMHB - Math Part-II

<span lang="EN-USMHB - Math Part-II

<span lang="EN-USMHB - Math Part-II

<span lang="EN-USMHB - Math Part-II

<span lang="EN-USMHB - Math Part-II

<span lang="EN-USMHB - Math Part-II

<span lang="EN-USMHB - Math Part-II

<span lang="EN-USMHB - Math Part-II