Q. 25.0( 2 Votes )

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Answer :

Let us name the different coordinate in the above question figure:


CBI + CBA = 180° (linear pair of angles at a vertex)


105° + CBA = 180°


CBA = 180° - 105°


CBA = 65°


BAH + BAC = 180° (linear pair of angles at a vertex)


BAH + 35° = 180°


BAH = 180° - 35°


BAH = 145°


In Δ ABC,


A + B + C = 180° (Sum of the angles of triangle is 180°)


35° + 65° + C = 180°


100° + C = 180°


C = 180° - 100°


C = 80°


ACB + ACJ = 180° (linear pair of angles at a vertex)


80° + ACJ = 180°


ACJ = 180° - 80°


ACJ = 140°


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