# A ladder is placed against a wall such that it just reaches the top of thewall. The foot of the ladder is 1.5 m away from the wall and the ladder isinclined at an angle of 60 owith the ground. Findthe height of the wall.

Given:

Distance of the ladder from the wall, d = BC = 1.5 m

Angle of elevation, θ = 60°

To find: Height of the wall, h:

Solution:

Let AC be the ladder and B be the foot of the wall.

In right angled Δ ABC,

tan [θ] = Opposite / Adjacent

Here θ = 60°

And also the opposite side is AB and the adjacent side is BC

tan 60 o = AB/BC

tan 60 o = AB/BC

AB = BC tan 60 o

We know that BC = 1.5m

= 1.5 × (√ 3)

= 1.5 × 1.732

= 2.598 m

Therefore the height of the wall is 2.598 m.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
NCERT | Imp. Qs. on Applications of Trigonometry54 mins
Quiz | Applications of Trigonometry47 mins
RD Sharma | IMP Qs Discussion on Some Application of Trigonometry44 mins
Application of Trigonometry45 mins
Fundas of Trigonometry50 mins
Champ Quiz | Trigger on Trigonometry47 mins
Basics of TrigonometryFREE Class
NCERT | Imp. Qs. Discussion - Trigonometry44 mins
Smart Revision | Trigonometric Ratios41 mins
Basic Concepts of Trigonometry45 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses