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Let the number of girls and boys in the class be x each.

On a particular day

8 boys were absent

∴ number of boys present = x-8

Since, number of girls is twice the number of boys present on that day

x = 2(x-8)

Solving the brackets, we get

X = 2x-2 × 8

⇒ x = 2x-16

⇒ 16 = 2x-x

⇒16 = x

Hence, number of boys and girls in the class = 16 each