Q. 2

A 3 cm thick iron open box is made whose external dimensions are 78 cm x 54 cm x 12 cm. Find the weight of the box if its density is 60 gm/cm3.

Answer :



Thickness of the iron sheet = 3 cm

External dimensions at the box = 78 cm x 54 cm x 12 cm

Internal Dimensions of the box = (78 - 2 × 3) × (54 - 2 × 3) × (12 - 3) = 72 × 48 × 9 

Therefore, internal dimensions of the box = 72 m x 48 cm x 9 cm

Volume of the iron used in making the box 
          = External volume of the box - Internal volume 
          = 78 x 54 x 12 - 72 x 48 x 9
          = 50544 - 31104 = 19440 cm3

Weight = Volume x density
         = 19440 x 60 gm
         = 1166.4 kg

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