Q. 1 L

# Let’s resolve into factors:

2a^{6}-13a^{3}-24

Answer :

2a^{6}-13a^{3}-24

=2a^{6}-16a^{3} + 3a^{3}-24

=2a^{3}(a^{3}-8) + 3(a^{3}-8)

= (2a^{3} + 3) (a^{3}-8)

Apply the formula a^{3} - b^{3} = (a - b)(a^{2} + ab + b^{2}) in (a^{3}-8),

(a^{3}-8) = (a^{3}-2^{3})

= (a-2)(a^{2} + 4 + 2a)

So,

2a^{6}-13a^{3}-24= (2a^{3} + 3) (a-2)(a^{2} + 4 + 2a)

∴ the factors of 2a^{6}-13a^{3}-24 are (2a^{3} + 3) (a-2)(a^{2} + 4 + 2a).

Rate this question :

I/we factorise the following algebraic expressions:

y^{2} + 23y + 102

West Bengal - Mathematics

I/we factorise the following algebraic expressions:

a^{2} + a – 132

West Bengal - Mathematics

I/we factorise the following algebraic expressions:

x^{2} – x – 6

West Bengal - Mathematics

I/we factorise the following algebraic expressions:

x^{2} + x – 6

West Bengal - Mathematics

Let’s resolve into factors:

ax^{2} + (a^{2} + 1)x + a

West Bengal - Mathematics

Let’s resolve into factors

x^{2}y^{2} + 23xy-420

West Bengal - Mathematics

Let’s resolve the following algebraic expressions into factors by expressing them as the difference of two squares:

x^{2}-2x-3

West Bengal - Mathematics

Let’s resolve the following algebraic expressions into factors by expressing them as the difference of two squares:

3a^{2}-2a-5

West Bengal - Mathematics

Let’s resolve into factors:

ax^{2}-(a^{2}-2)x-2a

West Bengal - Mathematics

Let’s resolve into factors:

ax^{2}-(a^{2} + 1)x + a

West Bengal - Mathematics