Answer :

On comparing with standard quadratic equation that is

we have,


a = 3, b = + 14 and c = + 15


Now here,


Product a × c = 3 × 15 = + 45


Factors of 45; 1 × 45; 5 × 9;15 × 3


Sum should be b = + 14


From above factors ( + 9x + 5x)


will give + 14x sum


therefore + 14x is replaced by ( + 9x + 5x)


Now above eq. becomes



; taking x and + 5 common


(x + 9)(x + 3)


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