Q. 1 H4.3( 7 Votes )

# <span lang="EN-US

First five multiples of 3 are

3, 6, 9, 12, 15

First term a = 3

Second term t1 = 6

Third term t2 = 9

Common difference d = t2 – t1 = 9 – 6 = 3

Thus, By using sum of nth term of an A.P. we will find it’s sum

Where, n = no. of terms

a = first term

d = common difference

Sn = sum of n terms

We need to find S5

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