Answer :

Given ∠ACB = 65°

⇒∠ AOB = 2 × 65° = 130° {∵ The measure of an inscribed angle is half the measure of the arc intercepted by it.}

m(AB) = 130°

So, m(arc ACB ) = 360° - m(AB) {∵ Measure of a major arc = 360°- measure of its corresponding minor arc}

⇒m(arc ACB ) = 360° - 130° = 230°

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