Q. 1 F5.0( 1 Vote )

# For each pair of

Given, a pair of polynomial as 3x – 1, 3x3 – 10x2 + 9x – 2

Need to find out the first polynomial is factor of second and if not a factor need to find the remainder

To check 3x – 1 is a factor of 3x3 – 10x2 + 9x – 2 we must substitute x = in the second polynomial, we get as follows

3( )3 – 10( )2 + 9( ) – 2 =   – 2

=  – 3 – 2

= – 5

= 0

3x – 1 is not a factor

To find the remainder divide second polynomial by first polynomial

so, we can subtract a number from the second polynomial to get the remainder

3x3 – 10x2 + 9x – 2 = (3x – 1)q(x) + c

3x3 – 10x2 + 9x – 2 –c = (3x – 1)q(x)

c = ((3x3 – 10x2 + 9x – 2) – (3x – 1)) × q(x)

Now, substitute x = in the above equation we get =   – 2 – 0

c =  is the remainder

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

In each pair of pKerala Board Mathematics Part-2

In each pair of pKerala Board Mathematics Part-2

What first degreeKerala Board Mathematics Part-2

In each pair of pKerala Board Mathematics Part-2

In each pair of pKerala Board Mathematics Part-2

In each pair of pKerala Board Mathematics Part-2

For each pair of Kerala Board Mathematics Part-2

For each pair of Kerala Board Mathematics Part-2

For each pair of Kerala Board Mathematics Part-2

For each pair of Kerala Board Mathematics Part-2