Put x = 1 in x2 + 3x – 4, we get(1)2 + 3(1) – 4= 1 + 3 – 4= 0∵ x2 + 3x – 4 = 0 on putting x = 1∴ 1 is the root of the quadratic equation x2 + 3x – 4.

Q. 1 E5.0( 1 Vote )

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Answer :

Put x = 1 in x² + 3x – 4, we get

(1)² + 3(1) – 4

= 1 + 3 – 4

= 0

∵ x² + 3x – 4 = 0 on putting x = 1

∴ 1 is the root of the quadratic equation x² + 3x – 4.

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