Answer :

Given that OP = 5 cm

And AB = 24cm

We know that a perpendicular drawn from the center of a circle on its chord bisects

the chord.

∴ AP = PB = 12 cm

In the right angled ΔOAP using Pythagoras theorem,

⇒ OA^{2} = OP^{2} + AP^{2}

⇒ OA^{2} = 5^{2} + 12^{2}

⇒ OA^{2} = 25 + 144

⇒ OA^{2} = 169

⇒ OA = 13cm

Hence, The correct option is B.

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