Q. 1 D3.9( 16 Votes )

# Factorise.

5y^{2} + 5y – 10

Answer :

On comparing with standard quadratic equation that is

we have,

a = 5, b = + 5 and c = – 10

Now here,

Product a × c = 5 × – 10 = – 50

Factors of 50; 5 × 10; 25 × 2;50 × 1

Sum should be b = + 5

From above factors ( – 5y + 10y)

will give + 5y sum

therefore + 5y is replaced by ( – 5y + 10y)

Now above eq. becomes

; taking 5y and + 10 common

(y – 1)(5y + 10)

5(y – 1)(y + 2); 5 common

Note: if given equation’s constant a,b,c have common multiple take it out and then factorize.

Rate this question :

Factorise.

5y^{2} + 5y – 10

Factorise.

x^{2} – 10x + 9

Factorise.

20x^{2} – 26x + 8

Factorise.

m^{2} – 25m + 100

Factorise.

44x^{2} – x – 3

Factorise.

3x^{2} + 14x + 15

Factorise.

2x^{2} + x – 45

Factorise.

m^{2} – 23m + 120

Factorise.

p^{2} – 7p – 44

Factorise.

x^{2} + 9x + 18