Answer :

On comparing with standard quadratic equation that is

we have,


a = 5, b = + 5 and c = – 10


Now here,


Product a × c = 5 × – 10 = – 50


Factors of 50; 5 × 10; 25 × 2;50 × 1


Sum should be b = + 5


From above factors ( – 5y + 10y)


will give + 5y sum


therefore + 5y is replaced by ( – 5y + 10y)


Now above eq. becomes



; taking 5y and + 10 common


(y – 1)(5y + 10)


5(y – 1)(y + 2); 5 common


Note: if given equation’s constant a,b,c have common multiple take it out and then factorize.


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