Q. 1 D3.9( 16 Votes )

# Factorise.5y2 + 5y – 10

On comparing with standard quadratic equation that is we have,

a = 5, b = + 5 and c = – 10

Now here,

Product a × c = 5 × – 10 = – 50

Factors of 50; 5 × 10; 25 × 2;50 × 1

Sum should be b = + 5

From above factors ( – 5y + 10y)

will give + 5y sum

therefore + 5y is replaced by ( – 5y + 10y)

Now above eq. becomes  ; taking 5y and + 10 common

(y – 1)(5y + 10)

5(y – 1)(y + 2); 5 common

Note: if given equation’s constant a,b,c have common multiple take it out and then factorize.

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