(3y)2 - 2 × 3y × 4 + (4)2 - (4)2 + 2 = 0(3y)2 - 2 × 3y × 4 + (4)2 - 16 + 2 = 0(3y - 4)2 - 14 = 0(3y - 4)2 = 143y - 14 = ±√143y = 14 ± √14y = (14 ± √14)/3

Q. 1 D

Solve the followi

Class 10th MHB - Mathematics Part-1 Quadratic Equations

Answer :

(3y)² - 2 × 3y × 4 + (4)² - (4)² + 2 = 0

(3y)² - 2 × 3y × 4 + (4)² - 16 + 2 = 0

(3y - 4)² - 14 = 0

(3y - 4)² = 14

3y - 14 = ±√14

3y = 14 ± √14

y = (14 ± √14)/3

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