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# For each pair of

Answer :

Given, a pair of polynomial as x – 2, x3 + 3x2 – 4x – 12

Need to find out the first polynomial is factor of second and if not a factor need to find the remainder

To check x – 2 is a factor of x3 + 3x2 – 4x – 12 we must substitute x = 2 in the second polynomial, we get as follows

23 + 3(2)2 – 4(2) – 12 = 8 + 12 – 8 – 12 = 0

x – 2 is a factor

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