Answer :

Given, a pair of polynomial as x – 2, x^{3} + 3x^{2} – 4x – 12

Need to find out the first polynomial is factor of second and if not a factor need to find the remainder

⇒ To check x – 2 is a factor of x^{3} + 3x^{2} – 4x – 12 we must substitute x = 2 in the second polynomial, we get as follows

⇒ 2^{3} + 3(2)^{2} – 4(2) – 12 = 8 + 12 – 8 – 12 = 0

∴ x – 2 is a factor

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In each pair of pKerala Board Mathematics Part-2

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For each pair of Kerala Board Mathematics Part-2