Answer :

On comparing with standard quadratic equation that is

we have,


a = 1, b = + 24 and c = + 144


Now here,


Product a × c = 1 × 144 = 144


Factors of 144; 12 × 12; 24 × 6;144 × 1;


48 × 3; 72 × 2


Sum should be b = 24


From above factors (12y + 12y)


will give + 24y sum


therefore + 24 is replaced by ( + 12y + 12y)


Now above eq. becomes




; taking y and + 12 common


(y + 1)(y + 12)


Note: Try to find all factors of “c”, then choose from it that combination whose sum or difference give “b”


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