Q. 1 B4.2( 10 Votes )

# – 2, 0, 2, 4

B. – 2, 4, – 8, 16

C. – 2, – 4, – 6, – 8

D. – 2, – 4, – 8, – 16

Answer :

Given first term t_{1} = – 2

Common difference d = – 2

By using formula t_{n + 1} = t_{n} + d

t_{2} = t_{1} + d = – 2 + ( – 2) = – 2 – 2 = – 4

t_{3} = t_{2} + d = – 4 + ( – 2) = – 4 – 2 = – 6

t_{4} = t_{3} + d = – 6 + ( – 2) = – 6 – 2 = – 8

Hence, the A.P. is – 2, – 4, – 6, – 8

∴ correct answer is (C)

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<span lang="EN-USMHB - Mathematics Part-1

Attempt any five Maharashtra Board - Algebra Papers

<span lang="EN-USMHB - Mathematics Part-1

<span lang="EN-USMHB - Mathematics Part-1

Attempt any five Maharashtra Board - Algebra Papers

Attempt any five Maharashtra Board - Algebra Papers

<span lang="EN-USMHB - Mathematics Part-1

<span lang="EN-USMHB - Mathematics Part-1

<span lang="EN-USMHB - Mathematics Part-1

<span lang="EN-USMHB - Mathematics Part-1