Answer :

(4 – p)3 =(4)3 – [ 3 ×(4)2 × p ] + [ 3 ×(4)×(p)2 ] –(p)3


{ (a – b)3 = a3 – 3a2b + 3ab2 – b3 }


= 64 [3 × 6 × p ] + [ 3 × 4 × p2 ] p3


= 64 – 48p + 12p2 – p3


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